Couple of comments, I question how much of us he's seen if he says Jerheme Urban is in the 4 Wr set, he hadn't played in 9 games until he played in the last game. And he's assuming Boldin will play so he's completely unaware that Doucet has been the 4th WR for quite awhile now.
Second, am I the only one who notices that in the last 2 years the habitual fumbler Kurt Warner has fumbled only 2 more times than Aaron Rodgers has? 22 for Kurt, 20 for Rodgers and damn near identical number of attempts. Rodgers doesn't throw picks and he's much more athletic than Warner outside the pocket but he will put the ball on the turf and this is the biggest game of his career.
I watched NFL playbook on NFL net tonight and I learned quite a bit. Baldy, Sterling Sharpe(surprise) and Theismann all picked the Packers. And why, both Sharpe and Theismann pointed out that the Packers play a 3-4 and since most NFL teams don't, they are very good at confusing opposing QB's.
Really, last time I checked the Cards were a 3-4 team too! And while the Vikings were completely unconfused in both wins against the Packers 3-4(30 and 38 points in the wins), we all saw how confused Favre was against the Cards 3-4, 17 points and 2 picks and 2-3 more that easily could have been picked. The announcers spent the whole pregame talking up Favre and the whole 2nd half talking about how confused he was. Now Warner is 8-3 in playoff games career, Rodgers is 0-0, both teams play the 3-4, does it make any sense to point out it might confuse Warner but not point out it might confuse Rodgers too?
Baldy at least pointed out that any team that has Kurt Warner "has a chance" but he too thinks the Packers are the better team.
I have no idea how we'll play Sunday, nobody does that's what makes this team so crazy, but I do think it's just as likely if not more likely that Rodgers is going to be rattled than it is Warner will. They're a very good team and very hot but I still say if the Cards don't beat themselves with turnovers and penalties there isn't a better team in the entire NFC.